A piece of wire 10 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is minimum?
1 Answer
The length of wire required for the square will be
Explanation:
Let the side of the square have a length
The combined lengths of the square and rectangle will equal
Area of equilateral triangle of side length
The total area of both square and triangle =
So differentiating ..
Hope this helps.