How do you evaluate and simplify #1/(81^-(3/4))#?

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Answer 1 · 2018-03-22T13:04:09

#1/81^(-3/4)=27#

We use identities #1/a^(-n)=a^n# and #(a^m)^n=a^(mxxn)#

hence #1/81^(-3/4)#

= #81^(3/4)#

= #(3^4)^(3/4)#

= #3^(4xx3/4)#

= #3^3#

= #27#