How do you factor #-4x^2 - 23x + 6#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Adesh D. Mar 22, 2018 #(4x-1)(x+6)# Explanation: #-4x^2-23x+6 = 4x^2+23-6# #4x^2+24x-x-6 = 4x(x+6)-1(x+6)# therefore: #(4x-1)(x+6)# #x= -6 or +1# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2696 views around the world You can reuse this answer Creative Commons License