Question

How do you multiply `(3y-8)^2`?

Answer 1

`=9y^2-48y+64`

Explanation:

#(3y - 8)^2

`=(3y - 8)(3y - 8)`

Use the distributive property

`=(3y)(3y)+(3y)(-8)+(-8)(3+(-8)(-8)`

`=9y^2-24y-24y +64`

`=9y^2-48y+64`