How do you multiply (3y-8)^2? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Gazza Mar 23, 2018 =9y^2-48y+64 Explanation: #(3y - 8)^2 =(3y - 8)(3y - 8) Use the distributive property =(3y)(3y)+(3y)(-8)+(-8)(3+(-8)(-8) =9y^2-24y-24y +64 =9y^2-48y+64 Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply (x-2)(x+3)? How do you simplify (-4xy)(2x^4 yz^3 -y^4 z^9)? How do you multiply (3m+1)(m-4)(m+5)? How do you find the volume of a prism if the width is x, height is 2x-1 and the length if 3x+4? How do you multiply (a^2+2)(3a^2-4)? How do you simplify (x – 8)(x + 5)? How do you simplify (p-1)^2? How do you simplify (3x+2y)^2? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2328 views around the world You can reuse this answer Creative Commons License