Question

How do you multiply `(3x +2) (3x - 2)`?

Answer 1

`9x^2-4`
You must distribute the values.

Explanation:

There is a method for this called FOIL. The means First, Outer, Inner, Last.
First-Multiply the first terms in each binomial, meaning `3x*3x`. `3*3=9`, and `x*x=x^2`. So the first term is `9x^2`.
Outer-Multiply the first term of the first binomial by the outermost term, meaning `3x*-2`, which equals `-6x`.
Inner-Multiply the innermost terms, so `2*3x`, which equals `6x`. `6x-6x` cancels out, so their will be no middle term.
Last-The last terms of each binomial, multiplied, which is `2*-2`, which equals `-4`.

Combine the remaining results, which are just `9x^2` and `-4`, to make `9x^2-4`.

You can check an answer such as this one by substituting an x value and seeing if the expressions are equal.