How do you solve #2cos^2(x)+ 4sin^2(x)=3 #?
1 Answer
Mar 24, 2018
Explanation:
Rewrite either completely in sine or completely in cosine.
#2(1- sin^2x) + 4sin^2x= 3#
#2 - 2sin^2x + 4sin^2x= 3#
#2sin^2x = 1#
#sin^2x= 1/2#
#sinx =+- 1/sqrt(2)#
#x = pi/4 + pi/2n#
Hopefully this helps!
