How do you graph #5x + y < 7#?
1 Answer
Mar 24, 2018
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
graph{(x^2+(y-7)^2-0.125)((x-1)^2+(y-2)^2-0.125)(5x+y-7)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause.
graph{(5x+y-7)<0 [-20, 20, -10, 10]}