Use divergent test to determine convergence of the following series?

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#sum_(n=0)^oo (pi/e)^n#

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Answer 1 · 2018-03-24T16:08:32

Divergent.

This is like a basic geometric series: if #|r| > 1#, then it's divergent, and if #|r| < 1#, then it's convergent.

Since #pi > e#, #r > 1#, therefore the series is divergent.

Hopefully this helps!