How do you simplify #(x+3)(x+3)#?
1 Answer
Mar 26, 2018
Explanation:
#"each term in the second factor is multiplied by each term"#
#"in the first factor"#
#rArr(color(red)(x+3))(x+3)#
#=color(red)(x)(x+3)color(red)(+3)(x+3)larrcolor(blue)"distribute"#
#=(color(red)(x)xx x)+(color(red)(x)xx3)+(color(red)(3)xx x)+(color(red)(3)xx3)#
#=x^2+3x+3x+9larrcolor(blue)"collect like terms"#
#=x^2+6x+9#