Question

How do you solve for y in `2x + 3y = 3`?

Answer 1

`y=-2/3x+1`

Explanation:

Move the `x` term to the right side, then divide everything by `3`:

`2x+3y=3`

`3y+2x=3`

`3y+2xcolor(blue)-color(blue)(2x)=3color(blue)-color(blue)(2x)`

`3ycolor(red)cancelcolor(black)(color(black)+2xcolor(blue)-color(blue)(2x))=3color(blue)-color(blue)(2x)`

`3y=3color(blue)-color(blue)(2x)`

`3y=-2x+3`

`color(blue)(color(black)(3y)/3)=color(blue)(color(black)(-2x+3)/3)`

`color(blue)(color(black)(color(red)cancelcolor(black)3y)/color(red)cancelcolor(blue)3)=color(blue)(color(black)(-2x+3)/3)`

`y=color(blue)(color(black)(-2x+3)/3)`

`y=color(blue)(color(black)(-2x)/3)+color(blue)(color(black)3/3)`

`y=color(blue)(color(black)(-2x)/3)+1`

`y=-2/3x+1`

That is solving for `y`. Hope this helped!