We want to expand the brackets firstly:
#3 xx 5=15#
#3xx-x^2=-3x^2#
This, therefore:
#x^2-21=3(5-x^2) -> x^2-21=15-3x^2#
As we want to isolate the #x# to one side, we do not want #-3x^2#, and therefore we do the opposite which is to #+3x^2#. Notice that these cancel out. Also, remember what we do to one side we must do to another.
#x^2-21=15-3x^2 -> 4x^2-21=15#
We do not want #-21#, as we would like to get #x# on its own, and therefore do the opposite to #-21# which is to #+21#, notice the #-21+21# cancels out. Also, remember what you do to one side you MUST do to another.
#4x^2-21=15 -> 4x^2=36#
As we would like the value of #x#, first we realise we have #4# lots of #x# and divide both sides by #4#
#4x^2=36 -> x^2=9#
As we would like #x#, we need to #sqrt# as that it the opposite to #^2#, notice the #^2# cancels out. Also, remember to do this to both sides. We must also remember to take both square roots as they both satisfy the original equation
#x^2=9 -> x=+-sqrt9=+-3#
#therefore# #x=+-3#
