Question

How do you solve the system of equations `2x + 3y = 5` and `x - 2y = 6`?

Answer 1

`(x,y)=(4,-1)`

Explanation:

`x=2y+6` in the second equation, define x in terms of y
`2(2y+6)+3y=5` plug back into the first equation
`4y+12+3y=5` distribute
`7y+12=5`
`7y=-7`
`y=-1` solve for y
Then, go back to the other equation and plug this value in for y
`x=2(-1)+6`
`x=-2+6`
`x=4`