If the sum of three consecutive odd integers is 81, what are the integers?

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Answer 1 · 2018-03-30T13:03:35

The integers are 25,27,29

let n = the first integer
let n+ 2 = the second integer
let n+ 4 = the third integer

Then add them and set the three integers equal to 81.

$n + n + 2 + n + 4 = 81$ $n + n+ 2 + n + 4 = 81$ combining like terms gives

$3 n + 6 = 81$ $3n + 6 = 81$ subtract 6 from both sides

$3 n + 6 - 6 = 81 - 6$ $3n + 6-6 = 81-6$ this gives

$3 n = 75$ $3n = 75$ divide both sides by 3

$\frac{3 n}{3} = \frac{75}{3}$ $(3n)/3 =75/3$ the answer is

$n = 25$ $n = 25$

The first integer is 25
The second integer is 27
the third integer is 29