If the slope of the tangent to 4x^2+cx+2e^y=2 at x=0 is 4, then what is the value of c?
If the slope of the tangent to 4x^2+cx+2e^y=2 at x=0 is 4, then find c
If the slope of the tangent to
2 Answers
Apr 3, 2018
The value of
Explanation:
First we will solve for the value of
4(0)^2 +0(x) + 2e^y =2
2e^y = 2
e^y = 1
y = 0
We must find the first derivative because this gives us the slope of the tangent at
8x + c + 2e^y(dy/dx) = 0
2e^y(dy/dx) = -c - 8x
dy/dx= (-c - 8x)/(2e^y)
We want to find at what value of
4 = (-c - 8(0))/(2(1)
8 = -c
c = -8
Hopefully this helps!
Apr 3, 2018