How do you simplify radical 8?

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Answer 1 · 2018-04-03T18:42:00

#sqrt(8) = sqrt(4)sqrt(2) = 2sqrt(2)#

When simplifying radical expressions, one should try to factor each radicand into a product of perfect squares.

Answer 2 · 2018-04-03T18:55:52

#2sqrt2#

when using surd laws we know:

#sqrtab =sqrta xx sqrt b#

Therefore:

#sqrt8 =sqrt4xxsqrt2#

Simplifying:

Using our squared numbers:

#sqrt4 =2#

#-> sqrt8 =2sqrt2#

As you still have #sqrt2# and then you stick the #2# in front of the root