How much work does it take to raise a #7 kg # weight #23 m #?

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Answer 1 · 2018-04-03T23:31:40

It takes 1578 J.

By the principle of conservation of energy, the work done getting it up there is equal to the gain in gravitational potential energy.

The gain in gravitational potential energy is given by

#DeltaGPE = m*g*Deltah = 7 kg*9.8 m/s^2*23 m = 1578 J#

I hope this helps,
Steve

Answer 2 · 2018-04-04T00:34:44

#1577.8# joules

The work done is given by the equation,

#W=F*d#

#F# is the force in newtons

#d# is the distance moved in meters

And so, the force is the weight of the box, which is #7 \ "kg"*9.8 \ "m/s"^2=68.6 \ "N"#.

Therefore, the work done is:

#W=68.6 \ "N"*23 \ "m"#

#=1577.8 \ "J"#