Question

How do you find the roots for `49x^2-14x-3`?

Answer 1

`- 1/7, and 3/7`

Explanation:

Use the new Transforming Method (Socratic, Google Search):
`y = 49x^2 - 14x - 3 = 0`
Transformed equation:
`y' = x^2 - 14x - 147 = 0`
Method: Find 2 real roots of y', then, divide them by a = 49.
Find 2 real roots of y', that have opposite signs, knowing their sum (-b = 14) and their product (ac = - 147). They are -7, and 21.
The 2 real roots of y are:
`x1 = -7/a = -7/49 = - 1/7`, and `x2 = 21/49 = 3/7`