How do you factor completely w^2 - w^2 y^4? Algebra Polynomials and Factoring Factoring Completely 1 Answer JL ยท Stefan V. Apr 4, 2018 w^2(1+y)(1-y)(1+y^2) Explanation: This is just a difference of squares. When you have a^2 - b^2, it's is equal to (a+b)(a-b). Just simply expand it to see why. In this case, it would be (w)^2 - (w*y^2)^2 (w- wy^2)(w + wy^2) w^2(1-y^2)(1+y^2) w^2(1+y)(1-y)(1+y^2) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 1530 views around the world You can reuse this answer Creative Commons License