Question

How do you simplify `(10xsqrt8)/sqrt16`?

Answer 1

`5xsqrt2`

Explanation:

`(10xsqrt8)/sqrt16`
`(10xsqrt8)/(sqrt8*sqrt2)` [`sqrtab=sqrta*sqrtb`]
`(10x)/sqrt2`
`(sqrt2*10x)/(sqrt2*sqrt2)`
`(sqrt2*10x)/2`
`5xsqrt2`