How do you multiply $(5 + 2 i) (5 - 2 i)$ $(5 + 2i)(5 - 2i)$ ?

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How do you multiply $(5 + 2 i) (5 - 2 i)$ $(5 + 2i)(5 - 2i)$ ?

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Answer 1 · 2018-04-05T04:46:14

$25 - 4 i^{2}$ $25-4i^2$

Explanation:

It matters not if $i$ $i$ is an imaginary number or not - the laws of algebra applies equally to all terms.
There is no difference between $(5 + 2 i) (5 - 2 i)$ $(5+2i)(5-2i)$ and $(5 + 2 x) (5 - 2 x)$ $(5+2x)(5-2x)$ .

Therefore, the answer is $25 - 4 i^{2}$ $25-4i^2$ .

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How do you multiply $(5 + 2 i) (5 - 2 i)$ $(5 + 2i)(5 - 2i)$ ?

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How do you multiply (5 + 2i)(5 - 2i)(5+2i)(5−2i) (5 + 2i)(5 - 2i)?

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How do you multiply $(5 + 2 i) (5 - 2 i)$ $(5 + 2i)(5 - 2i)$ ?