Question

What is the vertex of `y= x^2-5x-8`?

Answer 1

Vertex is `(5/2,-57/4)`

Explanation:

`y=x^2-5x-8`

Vertex is given by `x=-b/(2a)` where a,b refers to `ax^2+bx+c=0`

Therefore, `x=-b/(2a)=5/(2times1)=5/2`

Sub `x=5/2` into `y=x^2-5x-8` to get the y-value

`y=-57/4`

Vertex is `(5/2,-57/4)`