Question

The length of a rectangle is four times its width. If the perimeter of the rectangle is 70yd, how do you find its area?

Answer 1

`A=196yd^2`

Explanation:

The perimeter is defined as `p=2a+2b`

If `a=4b`,
`perimeter=8b+2b=10b`
`70=10b|:10`
`7yd=b`
`a=7*4=28yd`

The area of a rectangle is defined as `A=a*b`
`A=7*28=196yd^2`