Question

How do you solve `(x + 9) ^ { 2} - 36= 0`?

Answer 1

`x=-3 or -15`

Explanation:

`(x+9)^2`=36

`(x+9)=` `\pmsqrt(36)`

`x+9=6` or `x+9=-6`

`x=-3` or `x=-15`

Answer 2

`x=-15" or "x=-3`

Explanation:

`"subtract 36 from both sides"`

`(x+9)^2cancel(-36)cancel(+36)=0+36`

`rArr(x+9)^2=36`

`color(blue)"take the square root of both sides"`

`rArrx+9=+-sqrt36larrcolor(blue)"note plus or minus"`

`rArrx=-9+-6`

`rArrx=-9-6=-15`

`"or "x=-9+6=-3`