What is the vertex of # y= x^2 - 4x - 3#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Mark D. Apr 8, 2018 #(2,-7)# Explanation: #(-b)/(2a)# is the #x# value for the maximum/minimum (vertex) of a quadratic graph. Work out what this value is and put it into the equation to find the #y# value. #(--4)/(2)#=#4/2#=2 #x=2# #=># #y=2^2-4xx2-3# #=># #y=4-8-3# #y=-7# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1056 views around the world You can reuse this answer Creative Commons License