Question

What is the the vertex of `y =-x^2-3x-6`?

Answer 1

`(-3/2,-3/2)`

Explanation:

`(-b)/(2a)` is the `x` coordinate at this point

`(--3)/(2xx-1)` =`3/(-2)`

Put this value into the equation to find the `y` value

`(-3/(-2))^2-3xx(3/(-2))-6`

= `9/4+9/4-6`= `18/4-6`

=`-3/2`