How do you write a line through: (4-2), parallel to y=x+2?

2 Answers
Apr 11, 2018

Equation of parallel line through (4,-2) is

#color(maroon)(y = x - 6#

Explanation:

Standard form of slope-intercept equation is

#y = mx + c, " where m is the slope and c the y-intercept"#

Given equation is #y = x + 2"

Hence #Slope = m = 1#

#"Parallel line will also have the same slope m = 1"#

Having known slope and a point on the line, Equation for the same is

#(y - y_1 = m * (x - x_1)#

#y + 2 = 1 * (x - 4)#

#color(maroon)(y = x - 4 - 2 = x - 6#

Apr 11, 2018

#y=x-6#

Explanation:

Parallel lines have the same slope (in this case, the slope is 1).

Slope-intercept form of a line: #y=mx+b# where #m# represents slope and #b# the y-intercept

#y=x+b rarr# This is our current equation (we don't know the y-intercept).

Let's plug in the point given to us: #(4, -2)#

#-2=4+b#

#b=-6 rarr# This is the y-intercept

Our equation is #y=x-6#