Question

What is the distance between `(22,25,7)` and `(31,40,0)`?

Answer 1

`sqrt(355)~~18.8`

Explanation:

The distance between `(x_1,y_1,z_1)` and `(x_2,y_2,z_2)` is given by `sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)`

So for these two points we have:
`sqrt((31-22)^2+(40-25)^2+(0-7)^2)=sqrt((9)^2+(15)^2+(-7)^2)=sqrt(81+225+49)=sqrt(355)~~18.8`