A model train with a mass of $4 kg$ is moving along a track at $6 (cm)/s$ . If the curvature of the track changes from a radius of $36 cm$ to $48 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-04-14T17:15:42

The change in centripetal force is $=0.01N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=4kg$

The velocity of the train is $v=0.06ms^-1$

The radii of the tracks are

$r_1=0.36m$

and

$r_2=0.48m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=4*0.06^2/0.36=0.04N$

$||F_2||=4*0.06^2/0.48=0.03N$

$DeltaF=F_1-F_2=0.04-0.03=0.01N$

A model train with a mass of 4 kg4 kg is moving along a track at 6 (cm)/s6 (cm)/s. If the curvature of the track changes from a radius of 36 cm36 cm to 48 cm48 cm, by how much must the centripetal force applied by the tracks change?