Question

How do you solve `3(x + 2) > x`?

Answer 1

x>-3.

Explanation:

`3(x+2) > x`
=> `3x+6 > x`
=> `3x+6-x > x-x` ; (subtract x from both sides)
=>`2x+6 > 0`
=>`2x+6-6 > 0-6`; (subtract 6 from both sides)
=> 2x > -6
now finally divide by 2 on both sides to get,
=> `x > -3`

Answer 2

`x> -3`

Explanation:

Expand:

`3(x+2)>x -> 3x+6>x`

Get `x` on one side, then minus `6`

`3x+6>x -> 2x> -6`

Divide by `2`:

`x> -3`

Remember what we do on one side, we do to the other. Use this when doing all the steps above