How do you convert $(6, 0)$ to polar form?

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Answer 1 · 2018-04-15T03:42:02

Polar coordinates $(r, theta) = (6, 0)$

To convert from Cartesian Coordinates $(x,y)$ to Polar Coordinates $(r,theta)$ :

$r = sqrt( x^2 + y^2 )$

$θ = tan^-1 ( y / x )$

Given $x = 6, y = 0$

$r = sqrt(6^2) = 6$

$tan theta = 0 / 6 = 0 " or " theta = 0$

How do you convert (6, 0) (6, 0) to polar form?