How do you find the amplitude and period of #y=1/2sintheta#?

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Answer 1 · 2018-04-15T15:32:26

Amplitude is #color(blue)(1/2)#

#"Period"=color(blue)(2pi)#

If we express the sine function in the following way:

#y=asin(bx+c)+d#

Then:

# \ \ \bb|a| \ \ \ ="the amplitude"#

#bb((2pi)/|b|) \ \="the period"#

#bb((-c)/b)= "the phase shift"#

# \ \ \ \bbd \ \ \="the vertical shift"#

For given function we have:

#|a|=1/2#

So amplitude is #color(blue)(1/2)#

#|b|=1#

#"period"=(2pi)/|b|=(2pi)/1=color(blue)(2pi)#

GRAPH:

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