How do you solve #-a+6<=5#?

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Answer 1 · 2018-04-19T01:30:38

#a <= 1#

First: use the additive inverse:
#-a + 6 <= 5#
#-a <= -1#
#a <= 1#

There's your answer!

Answer 2 · 2018-04-19T01:35:38

#a>=1#

Solve:

#-a+6<=5#

Subtract #6# from both sides.

#-a<=5-6#

Simplify.

#-a<=-1#

Multiply both sides by #-1#. This will reverse the signs and the inequality.

#a>=1#