How do you solve the inequality #1/2<n/6#?
1 Answer
Apr 19, 2018
Explanation:
#"multiply both sides by 6"#
#cancel(6)^3xx1/cancel(2)^1< cancel(6)xxn/cancel(6)#
#rArr3< n" or "n>3#
#"multiply both sides by 6"#
#cancel(6)^3xx1/cancel(2)^1< cancel(6)xxn/cancel(6)#
#rArr3< n" or "n>3#