How do you factor $4 a b + 1 - 2 a - 2 b$ $4ab+1-2a-2b$ ?

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Answer 1 · 2018-04-21T00:18:34

$4 a b + 1 - 2 a - 2 b = (1 - 2 a) (1 - 2 b)$ $4ab+1-2a-2b=(1-2a)(1-2b)$

$4 a b + 1 - 2 a - 2 b$ $4ab+1-2a-2b$

It's not really necessary, but let's commute the terms a little.

$= 1 - 2 a - 2 b + 4 a b$ $=1-2a-2b+4ab$

Now factor out $- 2 b$ $-2b$ from the last two terms.

$= (1 - 2 a) - 2 b (1 - 2 a)$ $=(1-2a)-2b(1-2a)$

Now factor $(1 - 2 a)$ $(1-2a)$ out of both terms.

$= (1 - 2 a) (1 - 2 b)$ $=(1-2a)(1-2b)$

How do you factor 4ab+1−2a−2b4ab+1-2a-2b?