How do you factor the expression #x^2 - 10x + 25#?

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Answer 1 · 2018-04-22T19:48:00

#x²-10x+25=(x-5)²#

#x²-10x+25#

#Delta=b²-4ac#

#Delta=(-10)²-4*1*25#

#Delta=100-100#

#Delta=0#

So:

#x=-b/(2a)#

#x=10/2=5#

So :

#x²-10x+25=(x-5)²#

\0/ here's our answer !

Answer 2 · 2018-05-17T23:10:03

#x²-10x+25=(x-5)²#

#x²-10x+25#

#=x²-5x-5x+25#

#=x(x-5)-5(x-5)#

#=(x-5)(x-5)#

#=(x-5)²#

\0/ here's our answer !

Answer 3 · 2018-08-05T02:32:31

#(x-5)^2#

To factor this, let's do a little thought experiment:

What two numbers sum up to the middle term (#-10#) and have a product of the last term (#25#)?

After some trial and error, we arrive at #-5# and #-5#. This means we can factor this as

#(x-5)(x-5)#, which can be alternatively written as #(x-5)^2#.

Hope this helps!