How do you solve #(x+7)^(3/2)-20=7#?

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Answer 1 · 2018-04-22T22:57:15

#x=2#

#(x+7)^(3/2) -20 = 7#

Rearrange equation.

#(x+7)^(3/2) = 27#

To get rid of the power, first cube root it and then square it.

#((x+7)^(3/2*1/3)) = 27^(1/3)#

#(x+7)^(3/6) = 3 -> (x+7)^(1/2) = 3#

#(x+7)^(1/2 * 2) = 3^2 -> x+7 = 9#

Rearrange equation to make #x# the subject.

#x+7 = 9 -> x= 9-7#
#x=2#