How do you simplify #(x^2+5x+6) / (x-4)#?

1 Answer
Apr 22, 2018

Don't know that you would call these "simplifications" but..
#(x^2+5x+6)/(x-4)=((x+3)(x+2))/(x-4)# or # x+9 + 36/(x-4)#

Explanation:

You could do the simplification with (for example, synthetic division):

#{: (color(white)("xxx")," | ",color(gray)(x^2),color(gray)(x^1),color(gray)(x^0)), (," | ",1,5,6), (ul(+color(white)("x"))," | ",ul(color(white)("xxx")),ul(4),ul(36)), (xx4," | ",1,9,42), (," | ",color(gray)(x^1),color(gray)(x^0),color(blue)"R") :}#