How do you factor ${(x - 2 y)}^{2} - 3 x (x - 2 y)$ $(x - 2y)^2 - 3x(x - 2y)$ ?

Question

4408 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-23T22:46:50

$(x-2y)²-3x(x-2y)=-(3x+2y)(x-2y)$

$(x-2y)²-3x(x-2y)$
$=color(red)((x-2y))(x-2y)color(red)(-3x)(x-2y)$
$=((x-2y)-3x)(x-2y)$
$=(-3x-2y)(x-2y)$
$=-(3x+2y)(x-2y)$
\0/ here's our answer!

How do you factor (x - 2y)^2 - 3x(x - 2y)(x−2y)2−3x(x−2y)(x - 2y)^2 - 3x(x - 2y)?