Question

What is the distance between #(8, 6, 2) `and`(3, 6, 2) #?

Answer 1

5 units

Explanation:

We know the distance formula
d = `sqrt((x2-x2)^2+(y2-y1)^2+(z2-z1)^2)`
Therefore,
d = `sqrt((3-8)^2+(6-6)^2+(2-2)^2)`
d = `sqrt((-5)^2+(0)^2+(0)^2)`
d = `sqrt(25`
d = 5 Units

Answer 2

These only differ in one of the three coordinates, so the distance is the (absolute) difference between the remaining coordinate: `8-3` gives a distance of `5`.

Explanation:

This is my first answer where there's already another answer. I've been denoobed. Thanks, Socratic!