What is the simplified radical form of #sqrt(80)#?
1 Answer
Apr 26, 2018
Explanation:
#"using the "color(blue)"law of radicals"#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#rArrsqrt80#
#=sqrt(16xx5)=sqrt16xxsqrt5=4sqrt5#