How do you simplify #sqrt24#?

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Answer 1 · 2018-04-27T02:28:03

#2sqrt6#

#sqrt24#

The largest factor of #24# which can be square rooted is #4#:
#sqrt(4 * 6)#

Split it up:
#sqrt4 * sqrt6#

Simplify #sqrt4#:
#2 * sqrt6#

which becomes:
#2sqrt6#

Hope this helps!

Answer 2 · 2018-04-27T02:30:58

#sqrt24=color(blue)(2sqrt6#

Simplify:

#sqrt24#

Prime factorize #24#.

#sqrt24=sqrt(2xx2xx2xx3)#

Group the same prime factors into pairs.

#sqrt24=sqrt((2xx2)xx2xx3)#

Rewrite the pair in exponent form.

#sqrt24=sqrt(2^2xx2xx3)#

Apply rule #sqrt(a^2)=a#.

#sqrt24=2sqrt6#