Question

How do you convert the polar coordinate `(-2,(7pi)/8)` into rectangular coordinates?

Answer 1

`(1.84,-0.77)`

Explanation:

Given `(r,theta)`, `(x,y)` can be found by doing `(rcostheta,rsintheta)`

`r=-2`
`theta=(7pi)/8`

`(x,y)->(-2cos((7pi)/8),-2sin((7pi)/8)~~(1.84,-0.77)`