How do you factor 48y^2 - 72xy + 27x^248y272xy+27x2?

1 Answer
Apr 28, 2018

The answer is 3(3x-4y)^23(3x4y)2

Explanation:

In the given expression we can see that the coefficients of the polynomials are 48,72 48,72 and 2727 these numbers are divisible by 33
When you take 3 common from these numbers this expression becomes:
3(9x^2-24xy+16y^2)3(9x224xy+16y2)
and when we factorise 9x^2-24xy+16y^29x224xy+16y2 we get (3x-4y)^2(3x4y)2
so finally we get 3(3x-4y)^23(3x4y)2 as our answer.