How do you divide (x^4 + 2x^3 +3x -1) /(x^2+2)?

1 Answer
Apr 29, 2018

Using the distribution method, you can expand the expression.

Explanation:

(x^4+2x^3+3x-1)/(x^2+2)

distribute the (x^4+2x^3+3x-1) to x^2 and 2 and now we get:

(x^4+2x^3+3x-1)/x^2 + (x^4+2x^3+3x-1)/2

we can further distribute x^2 and 2 to (x^4+2x^3+3x-1):

(x^4/x^2+(2x^3)/x^2+(3x)/x^2-1/x^2)+((x^4)/2+(2x^3)/2+(3x)/2-1/2)

This is the simplified version:
x^2+2x+3/x-1/x^2+x^4/2+x^3+1.5x-1/2

Sorry but I'm not sure of what you are trying to find so I can only give this answer.