How do you solve by factoring $2 y^{3} + 7 y^{2} - 30 y = 0$ $2y^3+7y^2-30y=0$ ?

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Answer 1 · 2018-05-02T14:10:33

$y = 0 or - 6 or \frac{5}{2}$ $y=0 or -6 or 5/2$

$2 y^{3} + 7 y^{2} - 30 y = 0$ $2y^3+7y^2-30y=0$

Factor $y$ $y$ out,

$y (2 y^{2} + 7 y - 30) = 0$ $y(2y^2+7y-30)=0$

Factor further,

$y (y + 6) (2 y - 5) = 0$ $y(y+6)(2y-5)=0$

Solve,

$y = 0 or - 6 or \frac{5}{2}$ $y=0 or -6 or 5/2$

How do you solve by factoring 2y^3+7y^2-30y=02y3+7y2−30y=02y^3+7y^2-30y=0?