How do you factor #8z^2 + 16z - az - 2a#?
1 Answer
May 2, 2018
Explanation:
#color(blue)"factor by grouping"#
#rArrcolor(red)(8z)(z+2)color(red)(-a)(z+2)#
#"take out the "color(blue)"common factor "(z+2)#
#=(z+2)(color(red)(8z-a))#
