How do you factor $x^2-6x-4$ ?

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Answer 1 · 2018-05-04T00:25:16

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$x^2-6x-4$ is in the form of $ax^2+bx+c$

$x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(6+-sqrt(36+16))/(2)$

$x=(6+-sqrt52)/2$

$x=(6+-sqrt(4*13))/2$

$x=(6+-2sqrt13)/2$

$x=3+-sqrt13$

How do you factor x^2-6x-4x^2-6x-4?