How do you foil #(2x-5)(x+3)#?

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Answer 1 · 2018-05-06T19:38:49

#2x^2 + x -15#

F.O.I.L.

First, Outer, Inner Last

Multiply your first terms:

(2x - 5)(x + 3)

#2x * x = 2x^2#

Multiply your outer terms:

(2x - 5)(x + 3)

#2x * 3 = 6x#

Multiply your inner terms:

(2x - 5)(x + 3)

#-5 * x = -5x#

Multiply your last terms:

(2x -5)(x + 3)

#-5 * 3 = -15#

Add all your terms together.

#2x^2 + 6x - 5x - 15#

Simplify.

#2x^2 + x -15#