Question

What is the vertex of `y= 2x^2 + 8x − 3`?

Answer 1

You can find the line of symmetry, and then plug in to find the `y` point that correlates to this line.

Explanation:

To do this, use

`-b/(2a)`

to give you the line of symmetry. So

`-8/(2 * 2)=-2`

Now, you can plug this back into the original so you will receive

`y=2(-2)^2+8(-2)-3`

This comes out to a value of

`y = 8 - 16 - 3`

`y=-11`

So the vertex will be `(-2,-11)`.

graph{2x^2 + 8x -3 [-5, 5, -15, 5]}