What is the vertex of #y= 4(x-1)^2-1 #?

1 Answer
May 8, 2018

#"vertex "=(1,-1)#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|))#

#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#

#y=4(x-1)^2-1" is in this form"#

#"with "h=1" and "k=-1#

#rArrcolor(magenta)"vertex "=(1,-1)#
graph{4(x-1)^2-1 [-10, 10, -5, 5]}